====== Eindeutige ID eines Android-Gerätes ======
**DEPRECATED** //Bitte alternative Methode weiter unten verwenden//\\
Um eine eindeutige ID eines Android-Gerätes zu ermitteln, kann folgendes Code-Snippet genutzt werden:

<code java AndroidUID.java>
import java.util.UUID;

    private static String getUniquePsuedoID() {
        // If all else fails, if the user does have lower than API 9 (lower
        // than Gingerbread), has reset their phone or 'Secure.ANDROID_ID'
        // returns 'null', then simply the ID returned will be solely based
        // off their Android device information. This is where the collisions
        // can happen.
        // Thanks http://www.pocketmagic.net/?p=1662!
        // Try not to use DISPLAY, HOST or ID - these items could change.
        // If there are collisions, there will be overlapping data
        String m_szDevIDShort = "35" + (android.os.Build.BOARD.length() % 10) + (android.os.Build.BRAND.length() % 10) + (android.os.Build.CPU_ABI.length() % 10) + (android.os.Build.DEVICE.length() % 10) + (android.os.Build.MANUFACTURER.length() % 10) + (android.os.Build.MODEL.length() % 10) + (android.os.Build.PRODUCT.length() % 10);

        // Thanks to @Roman SL!
        // http://stackoverflow.com/a/4789483/950427
        // Only devices with API >= 9 have android.os.Build.SERIAL
        // http://developer.android.com/reference/android/os/Build.html#SERIAL
        // If a user upgrades software or roots their phone, there will be a duplicate entry
        String serial;
        try {
            serial = android.os.Build.class.getField("SERIAL").get(null).toString();

            // Go ahead and return the serial for api => 9
            return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
        } catch (Exception e) {
            // String needs to be initialized
            serial = "bewa"; // some value
        }

        // Thanks @Joe!
        // http://stackoverflow.com/a/2853253/950427
        // Finally, combine the values we have found by using the UUID class to create a unique identifier
        return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
    }
</code>


Eine alternative Variante, welche die Android ID ausliest sieht so aus:

<code java AndroidID.java>
import android.provider.settings;

public class RequestHelper {

    public static String getAndroidID(Context context) {
        return Settings.Secure.getString(context.getContentResolver(), Settings.Secure.ANDROID_ID);
    }
    
}
</code>